Optimal. Leaf size=105 \[ \frac{a^3 \sin ^5(c+d x)}{5 d}-\frac{5 a^3 \sin ^3(c+d x)}{3 d}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{3 a^3 \sin (c+d x) \cos ^3(c+d x)}{4 d}+\frac{13 a^3 \sin (c+d x) \cos (c+d x)}{8 d}+\frac{13 a^3 x}{8} \]
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Rubi [A] time = 0.11724, antiderivative size = 105, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {2757, 2635, 8, 2633} \[ \frac{a^3 \sin ^5(c+d x)}{5 d}-\frac{5 a^3 \sin ^3(c+d x)}{3 d}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{3 a^3 \sin (c+d x) \cos ^3(c+d x)}{4 d}+\frac{13 a^3 \sin (c+d x) \cos (c+d x)}{8 d}+\frac{13 a^3 x}{8} \]
Antiderivative was successfully verified.
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Rule 2757
Rule 2635
Rule 8
Rule 2633
Rubi steps
\begin{align*} \int \cos ^2(c+d x) (a+a \cos (c+d x))^3 \, dx &=\int \left (a^3 \cos ^2(c+d x)+3 a^3 \cos ^3(c+d x)+3 a^3 \cos ^4(c+d x)+a^3 \cos ^5(c+d x)\right ) \, dx\\ &=a^3 \int \cos ^2(c+d x) \, dx+a^3 \int \cos ^5(c+d x) \, dx+\left (3 a^3\right ) \int \cos ^3(c+d x) \, dx+\left (3 a^3\right ) \int \cos ^4(c+d x) \, dx\\ &=\frac{a^3 \cos (c+d x) \sin (c+d x)}{2 d}+\frac{3 a^3 \cos ^3(c+d x) \sin (c+d x)}{4 d}+\frac{1}{2} a^3 \int 1 \, dx+\frac{1}{4} \left (9 a^3\right ) \int \cos ^2(c+d x) \, dx-\frac{a^3 \operatorname{Subst}\left (\int \left (1-2 x^2+x^4\right ) \, dx,x,-\sin (c+d x)\right )}{d}-\frac{\left (3 a^3\right ) \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin (c+d x)\right )}{d}\\ &=\frac{a^3 x}{2}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{13 a^3 \cos (c+d x) \sin (c+d x)}{8 d}+\frac{3 a^3 \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{5 a^3 \sin ^3(c+d x)}{3 d}+\frac{a^3 \sin ^5(c+d x)}{5 d}+\frac{1}{8} \left (9 a^3\right ) \int 1 \, dx\\ &=\frac{13 a^3 x}{8}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{13 a^3 \cos (c+d x) \sin (c+d x)}{8 d}+\frac{3 a^3 \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{5 a^3 \sin ^3(c+d x)}{3 d}+\frac{a^3 \sin ^5(c+d x)}{5 d}\\ \end{align*}
Mathematica [A] time = 0.12669, size = 63, normalized size = 0.6 \[ \frac{a^3 (1380 \sin (c+d x)+480 \sin (2 (c+d x))+170 \sin (3 (c+d x))+45 \sin (4 (c+d x))+6 \sin (5 (c+d x))+780 d x)}{480 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.043, size = 121, normalized size = 1.2 \begin{align*}{\frac{1}{d} \left ({\frac{{a}^{3}\sin \left ( dx+c \right ) }{5} \left ({\frac{8}{3}}+ \left ( \cos \left ( dx+c \right ) \right ) ^{4}+{\frac{4\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}}{3}} \right ) }+3\,{a}^{3} \left ( 1/4\, \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+3/2\,\cos \left ( dx+c \right ) \right ) \sin \left ( dx+c \right ) +3/8\,dx+3/8\,c \right ) +{a}^{3} \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) +{a}^{3} \left ({\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.12049, size = 158, normalized size = 1.5 \begin{align*} \frac{32 \,{\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} a^{3} - 480 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} a^{3} + 45 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{3} + 120 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} a^{3}}{480 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.64661, size = 194, normalized size = 1.85 \begin{align*} \frac{195 \, a^{3} d x +{\left (24 \, a^{3} \cos \left (d x + c\right )^{4} + 90 \, a^{3} \cos \left (d x + c\right )^{3} + 152 \, a^{3} \cos \left (d x + c\right )^{2} + 195 \, a^{3} \cos \left (d x + c\right ) + 304 \, a^{3}\right )} \sin \left (d x + c\right )}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.46558, size = 272, normalized size = 2.59 \begin{align*} \begin{cases} \frac{9 a^{3} x \sin ^{4}{\left (c + d x \right )}}{8} + \frac{9 a^{3} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac{a^{3} x \sin ^{2}{\left (c + d x \right )}}{2} + \frac{9 a^{3} x \cos ^{4}{\left (c + d x \right )}}{8} + \frac{a^{3} x \cos ^{2}{\left (c + d x \right )}}{2} + \frac{8 a^{3} \sin ^{5}{\left (c + d x \right )}}{15 d} + \frac{4 a^{3} \sin ^{3}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{3 d} + \frac{9 a^{3} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} + \frac{2 a^{3} \sin ^{3}{\left (c + d x \right )}}{d} + \frac{a^{3} \sin{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{d} + \frac{15 a^{3} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} + \frac{3 a^{3} \sin{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} + \frac{a^{3} \sin{\left (c + d x \right )} \cos{\left (c + d x \right )}}{2 d} & \text{for}\: d \neq 0 \\x \left (a \cos{\left (c \right )} + a\right )^{3} \cos ^{2}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.39879, size = 119, normalized size = 1.13 \begin{align*} \frac{13}{8} \, a^{3} x + \frac{a^{3} \sin \left (5 \, d x + 5 \, c\right )}{80 \, d} + \frac{3 \, a^{3} \sin \left (4 \, d x + 4 \, c\right )}{32 \, d} + \frac{17 \, a^{3} \sin \left (3 \, d x + 3 \, c\right )}{48 \, d} + \frac{a^{3} \sin \left (2 \, d x + 2 \, c\right )}{d} + \frac{23 \, a^{3} \sin \left (d x + c\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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